answersLogoWhite

0

So far, the best and most general pattern found is that, over three, all prime numbers are of the form 6n +/- 1. In other words, they're either 6n - 1 or 6n + 1, for some n.

Here is why this is true.

We could do a proof by contradiction and assume that all the natural numbers greater than or equal to 5 are prime. (of course they are not!) We start with5 which is 6-1.

The numbers would then be 6n - 1, 6n, 6n + 1, 6n + 2, 6n + 3, 6n + 4, and 6n + 5 for some natural number n. If it is 6n, then the number is divisible by 6. When it is 6n + 2, the number is the same as 2(3n+1) so it is divisible by 2. Consider 6n + 3, the number is 3(2n+1), so it is divisible by 3. Last look at 6n + 4, the number is divisible by 2, for it's 2(3n + 2).

Therefore all numbers of the form 6n, 6n + 2, 6n + 3, and 6n + 4 are not prime. The only possibilities this leaves are 6n - 1 and 6n + 1.

This entire thing can be written more elegantly with congruences, but the goal here was simplicity!

There are many other patterns in primes. See the attached link to see them.

User Avatar

Wiki User

14y ago

Still curious? Ask our experts.

Chat with our AI personalities

LaoLao
The path is yours to walk; I am only here to hold up a mirror.
Chat with Lao
JudyJudy
Simplicity is my specialty.
Chat with Judy
DevinDevin
I've poured enough drinks to know that people don't always want advice—they just want to talk.
Chat with Devin

Add your answer:

Earn +20 pts
Q: Is there a pattern for prime numbers?
Write your answer...
Submit
Still have questions?
magnify glass
imp