So far, the best and most general pattern found is that, over three, all prime numbers are of the form 6n +/- 1. In other words, they're either 6n - 1 or 6n + 1, for some n.
Here is why this is true.
We could do a proof by contradiction and assume that all the natural numbers greater than or equal to 5 are prime. (of course they are not!) We start with5 which is 6-1.
The numbers would then be 6n - 1, 6n, 6n + 1, 6n + 2, 6n + 3, 6n + 4, and 6n + 5 for some natural number n. If it is 6n, then the number is divisible by 6. When it is 6n + 2, the number is the same as 2(3n+1) so it is divisible by 2. Consider 6n + 3, the number is 3(2n+1), so it is divisible by 3. Last look at 6n + 4, the number is divisible by 2, for it's 2(3n + 2).
Therefore all numbers of the form 6n, 6n + 2, 6n + 3, and 6n + 4 are not prime. The only possibilities this leaves are 6n - 1 and 6n + 1.
This entire thing can be written more elegantly with congruences, but the goal here was simplicity!
There are many other patterns in primes. See the attached link to see them.
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It appears to be consecutive prime numbers
Answer: Prime numbers are not random. Im sure if you were to graph them then you could find an equasion for the discovery of prime numbers. Therefore the pattern of prime numbers would have to follow that equasion what ever that is. Im only in 8th grade and so i could be horribly wrong however my hypothesis seems logical. Answer: They are not really random, but their distribution is fairly complicated.
Any two prime numbers will be relatively prime. Numbers are relatively prime if they do not have any prime factors in common. Prime numbers have only themselves as prime factors, so all prime numbers are relatively prime to the others.
Products of prime numbers are composite numbers.
The opposite of prime numbers are composite numbers.