The LCM of 4 and 8 is 8. The LCM of 6 and 10 is 30. The LCM of 7 and 8 is 56. The LCM of 9 and 12 is 36.
The LCM of 4, 8, and 56 is 6. Since 4 and 8 are factors of 56, 56 is the LCM of the set. The answer can be found by dividing the 3 numbers into their prime factors, in this case 4=2x2, 8=2x2x2, and 56=7x2x2x2. The lowest common multiple is the smallest number which has all of these prime factors in. That means it has to have two 2's in (from 4) three 2's in (from 8) and three 2's and a 7 from 56. In this case, all of the prime factors of 4 can be found in 8, and all of the prime factors of 8 are in 56, so the LCM (lowest common multiple) of these 3 is 56.
56 = 2*2*2*7 98 = 7*7*2 LCM of 56 = 2*2*2*7*7 or 392
8 and 560, respectively.
Yes because 7 times 8 = 56Yes 7 times 8 = 56
LCM of 7 8 and 14 is 56.
The LCM of 7 and 8 is 56.
The Least Common Multiple (LCM) for 7 8 2 is 56.
The least common multiple (LCM) of 7, 8, and 28 is 56.
The LCM is 56.
lcm(7, 8, 14) = 56 Using factorisation: 7 = 7 8 = 2³ 14 = 2 x 7 lcm = 2³ x 7 = 56
The LCM is: 56
For 14, 8, 7, 4 the LCM is: 56
7 and 8 have no common factors (other than 1) so their LCM is their multiple.That is, LCM of 7 and 8 is 7*8 = 56
The LCM is 56.
LCM(2, 4, 7, 8) = 56.
It is: 56