This would be a literally impossible task, because the set of all real numbers is uncountable and every real number except 0 is a factor of 38. Probably the questioner meant "integral factors", for which the answer is 1, 2, and 19.
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The factors of 27 are 1, 3, 9, and 27. The factors of 38 are 1, 2, 19, and 38.
The product of all the common prime factors is the GCF. The product of all common factors would vary according to the list.
The solution to the factorization - the factors are 1, 2, 19, 38
1, 2, 19, 38 1, 3, 13, 39
The factors of 38 are 1, 2, 19, and 38. There are four different factors. The prime factors of 38 are 2 and 19. There are two different prime factors.