An irrational number is a number that never ends. An example of an irrational square root would be the square root of 11.
The square root of 18 is an irrational number because it cannot be expressed as a fraction.
Nice question! The square root of (any number that isn't a perfect square) is irrational. No prime number is a perfect square. So the square root of any prime number is irrational.
No. The square root of an integer is either an integer, or an irrational number.
Yes. The square root of any number that is not a perfect square (like 9 or 36) is irrational.
The square root of 2 is 1.141..... is an irrational number
Because 3 is a prime number and as such its square root is irrational
This is impossible to prove, as the square root of 2 is irrational.
It is known that the square root of an integer is either an integer or irrational. If we square root2 root3 we get 6. The square root of 6 is irrational. Therefore, root2 root3 is irrational.
No; you can prove the square root of any positive number that's not a perfect square is irrational, using a similar method to showing the square root of 2 is irrational.
Yes. The square root of a positive integer can ONLY be either:* An integer (in this case, it isn't), OR * An irrational number. The proof is basically the same as the proof used in high school algebra, to prove that the square root of 2 is irrational.
It is a irrational number. Because the square root of every imperfect square is irrational number.
An irrational number is a number that never ends. An example of an irrational square root would be the square root of 11.
The square root of 27 is an irrational number
Yes. For example, the square root of 3 (an irrational number) times the square root of 2(an irrational number) gets you the square root of 6(an irrational number)
the square root of 26 is a irrational number
The square root of 94 is an irrational number