The sum of the first 2,006 positive, odd integers is 4,024,036.
The first odd positive integers are "1" and "3" which the sum is 4.
17 , 19 , 21 and 23 are the odd integers whose sum is 80 and the least integer is 17
The sum is four.
Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.
The sum of the squares of the first 1000 positive odd integers (from 12 to 19992) is 1333333000.
The two consecutive negative odd integers having 74 as the sum of their squares are -5 and -7.
112+92 is 202.
3 and 5
If you have two consecutive integers then one of them must be odd and the other must be even. The square of an odd integer must be odd, the square of an even integer must be even. The sum of an odd number and an even number must be odd. Thus, the sum of squares of any two consecutive numbers must be odd. Therefore, the question has no valid answer.
9 and 11 92 = 81 112 = 121 81+121 = 202
The sum of any three consecutive odd integers is going to give an odd result. It is impossible for the sum of an odd number of odd integers to equal an even number.
The sum of the first eleven positive odd integers is 121.
The sum of the first 2,006 positive, odd integers is 4,024,036.
The first odd positive integers are "1" and "3" which the sum is 4.
29 cannot be the sum of two odd integers. The sum of two odd integers is always an even integer.
There are no two consecutive integers that sum to 58. With two consecutive integers, one is even, the other is odd. The sum of an even number and an odd number is odd. 58 is even so cannot be the sum of two consecutive integers.