The formula for the sum of the squares of odd integers from 1 to n is n(n + 1)(n + 2) ÷ 6.
EXAMPLE : Sum of odd integer squares from 1 to 15 = 15 x 16 x 17 ÷ 6 = 680
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The sum of the first 2,006 positive, odd integers is 4,024,036.
The first odd positive integers are "1" and "3" which the sum is 4.
17 , 19 , 21 and 23 are the odd integers whose sum is 80 and the least integer is 17
The sum is four.
Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.