958 and 1437
479 and 958, among others.
1, 3, 19, 57, 479, 1437, 9101, 27303
Oh, dude, you're hitting me with some math vibes here. So, if the greatest common factor of two numbers is 479 and one is odd while the other is even, and they're not divisible by each other, then the smallest those two numbers could be is 479 and 958. The odd number would be 479 and the even number would be 958. Easy peasy lemon squeezy!
2 and 3 are relatively prime, so multiply 479 by each of them to get two numbers that have 479 as a greatest common factor and are not divisible by each other, one which will be even and one which will be odd.479 x 2 = 958479 x 3 = 1437Furthermore, this is the smallest solution. The two numbers are multiples of 479, so let's call them 479x and 479y, where 479x is even and 479y is odd. Then x must be even, and y must be odd. So x is at least 2. y is an odd number, and it can't be 1 otherwise 479y would be a factor of 479x. So y is at least 3. Theefore the two numbers are at least 479*2 and 479*3.
2 AND 3
958 and 1437
958 and 1437
958 and 1437
479 and 958, among others.
1, 3, 19, 57, 479, 1437, 9101, 27303
958 and 1437
Oh, dude, you're hitting me with some math vibes here. So, if the greatest common factor of two numbers is 479 and one is odd while the other is even, and they're not divisible by each other, then the smallest those two numbers could be is 479 and 958. The odd number would be 479 and the even number would be 958. Easy peasy lemon squeezy!
By any of its factors which are: 1, 11, 479 and 5269
A single number cannot have a greatest common factor because "common" refers to factors that two or more numbers have in common. You have only one, which is 479. Also, only one number can be the greatest.
479 is a prime number.
2 and 3 are relatively prime, so multiply 479 by each of them to get two numbers that have 479 as a greatest common factor and are not divisible by each other, one which will be even and one which will be odd.479 x 2 = 958479 x 3 = 1437Furthermore, this is the smallest solution. The two numbers are multiples of 479, so let's call them 479x and 479y, where 479x is even and 479y is odd. Then x must be even, and y must be odd. So x is at least 2. y is an odd number, and it can't be 1 otherwise 479y would be a factor of 479x. So y is at least 3. Theefore the two numbers are at least 479*2 and 479*3.