Well, honey, I hate to break it to you, but the numbers 8 and 36 are not multiples of 5. Natural numbers are those positive integers starting from 1, and multiples of 5 are numbers that can be divided by 5 without any remainder. So, in this case, you're barking up the wrong tree.
Multiples of 50 are the only numbers that are both. All other multiples of 5 aren't.
Numbers which are the factors of thirty and multiples of five are 5, 10, 15 and 30.
Do you mean common multiples? If so, then 30, 60, 90 etc. are common multiples of 30 and 5. If you mean multiples of 5 and factors of 30, that's 5, 15 and 30.
Any multiple of 15.
That isn't true.
Well, honey, I hate to break it to you, but the numbers 8 and 36 are not multiples of 5. Natural numbers are those positive integers starting from 1, and multiples of 5 are numbers that can be divided by 5 without any remainder. So, in this case, you're barking up the wrong tree.
Multiples are the numbers that can be divided by their factors. Like multiples of 2 are 2,4,6,8,10 and so on .The numbers obtained from the multiplication of 2 with all the natural numbers are the multiples of 2.
No. Odd numbers can be written as the sum of consecutive integers, but some multiples of odd numbers are even.
Every number has 1 as a factor.
Multiples of 50 are the only numbers that are both. All other multiples of 5 aren't.
Multiples of 5.
All multiples of 5 are numbers ending in either 5 or 0.
To find the numbers between 10 and 50 that are multiples of both 3 and 5, we need to find the numbers that are multiples of the least common multiple of 3 and 5, which is 15. The multiples of 15 between 10 and 50 are 15, 30, and 45. Therefore, there are 3 numbers between 10 and 50 that are multiples of both 3 and 5.
the common multiples of 5 and 6 is 30
Since you didn't specify a single number, and all numbers are multiples of themselves, the five smallest multiples are the counting numbers 1 to 5.
Since both 3 and 5 are prime numbers, only numbers that are multiples of its product are the numbers that are divisible by both. 15 is the LCM of 3 and 5 and hence all multiples of 15 are divisible by both 3 and 5