The sum of an odd number and an even number is an odd number.
3 + 23 7 + 19 13 + 13
(7 x 8) + (8 x 8) = 15 x 8 = 120
It's not entirely clear from the wording of your question what it is you want to know. Seven is a one-digit number. The sum of its digits is 7. Seven has two factors: 1 and 7. That sum is 8.
The prime numbers between 1 and 15 are 2, 3, 5, 7, 11, and 13. To find the sum, you simply add these numbers together: 2 + 3 + 5 + 7 + 11 + 13 = 41. Therefore, the sum of prime numbers between 1 and 15 is 41.
(15+7) +99
(x + 15)
the magic sum is 15
8x + 15 = 7 so 8x = 7 - 15: x = -1
7+8=15 15-6=9
If you add a single number - in this case minus seven - the "sum" is the number itself.
11+3+1=15 but 1 is not a prime number. 3 + 5 + 7 = 15
The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56
(7*8)+(7+8) = 56+15 = 71
If x + 7 = 15, then 15 - 7 = x, therefore x = 8.If x = 8, then 4x is equal to 4 x 8 = 32.
8 + 7 = 15
-7