If you say so!
Placing a question mark at the end of a phrase does not make it a sensible question. Try to use a whole sentence to describe what it is that you want answered.
No. There is no set of three consecutive even integers with a sum of 40.
4, 6, 8, 10
No.Let the four numbers be (n-1), n, (n+1), (n+2).Their sum is 4n + 2 = 2(2n + 1)If 2000 is the sum of four consecutive integers, then:2(2n+1) = 2000⇒ 2n + 1 = 1000⇒ 2n = 999but 999 is odd, not even and so n cannot be an integer; therefore 2000 is not the sum of four consecutive integers.
There are two consecutive even integers. The numbers are 118 and 120.
The sum is four.
The sum of the first four non-negative, consecutive, even integers is 20.
No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
The numbers are 82, 84, 86 and 88.
The integers are 5, 6, 7 and 8.
No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.
There are no two consecutive integers that sum to 58. With two consecutive integers, one is even, the other is odd. The sum of an even number and an odd number is odd. 58 is even so cannot be the sum of two consecutive integers.
The integers are -2, 0, 2 and 4.
The two consecutive, even integers are 350 and 352.
No two consecutive even integers satisfy that request.
There are none. The only four consecutive integers totaling 90 are 21, 22, 23 and 24.