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The prime factors must be less than 17 since four of them sum to 17. The possibilities are 2, 3, 5, 7, 11, and 13. Because there are four prime factors, since four odd numbers would add up to an even number, one of the prime factors must be even. The only even prime factor is 2, so it must be one of the prime factors.
Now, we need the remaining three prime factors that must sum to 17 - 2 = 15. If the prime factors are different, the only three that add to 15 are 3, 5, and 7. So, the four prime factors would be 2, 3, 5, and 7, which means the number is 2 x 3 x 5 x 7 = 210.
If the prime factors do not need to be different, we have more possibilities:
2, 5, 5, and 5: 250
2, 2, 2, and 11: 88
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The sum of your four prime factors is 17 What are you?
2, 3, 5, 7 are the 4 prime factors Number is: 210
Find the sum of the prime factors of 20?
Factors for 20 are: 1, 2, 4, 5, 10, 20 Prime Factors: 2, 5 sum of prime factors = 2 + 5 = 7
What is the smallest possible sum for 4 different prime numbers when the answer is a prime number?
The smallest four prime numbers are 2, 3, 5, 7, and their sum happens to be a prime.
What are the factors and prime factors of 272?
The factors of 272 are 1, 2, 4, 8, 16, 17, 34, 68, 136, and 272. The prime factors of 272 are 2, 2, 2, 2, and 17.
What are the factors and prime factors of 476?
The factors of 476 are 1, 2, 4, 7, 14, 17, 28, 34, 68, 119, 238, and 476. The prime factors of 476 are 2, 2, 7, and 17.
