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First, the only candidates are odd, so 41, 43, 45, 47, 49

45 is divisible by 5, and 49 by 7, leaving 41, 43, and 47

Now, you can try to divide these number by all of the odd numbers between 3 and themselves (as a simple algorithm), but you will not find that they are divisible by any number other than one and themselves. So, 41, 43, and 47 are prime.

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