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What are the three consecutive numbers of 180?
The numbers are 59, 60 and 61.
What four consecutive prime numbers add up to 220?
The four consecutive prime numbers that add up to 220 are: 47+53+59+61 = 220
Four consecutive prime numbers that add up to 220?
47, 53, 59, 61
What are 4 consecutive prime numbers that add up to 220?
224
Can you find four consecutive prime numbers that add up to 220?
47, 53, 59, 61
The sum of the squares of two consecutive positive numbers is 61?
5
The sum of the squares of two consecutive positive numbers is 61. What are the smaller numbers?
5
The sum of the square of two consecutive positive numbers is 61 what is the smaller number?
The two numbers are 52 + 62 = 25 + 36 = 61
The sum of the square of two consecutive positive numbers is 61?
25+36=61 is that what you want to hear?
The sum of the squares of two consecutive positive numbers is 61 What is the smaller number?
5.
What is The sum of the squares of two consecutive positive numbers is 61 what is the smaller number?
The numbers are 5 and 6.
The sum of the squares of two consecutive positive numbers is 61. What is the number?
There is no single number here. The two seed numbers are 5 and 6; their squares sum to 61.
The sum of the two consecutive positive numbers is 61 what is the smaller number?
30 + 31 = 61 The smaller number is therefore 30.
What two consecutives lie between 61?
The two consecutive numbers that lie between 61 are 62 and 63. Consecutive numbers are those that follow one another in order, so after 61, the next two are 62 and 63.
The sum of two consecutive number is 61 What are the numbers?
The numbers are 30 and 31.
What two consecutive numbers when added equal 123?
They are 61+62 = 123
The sum of the squares of two consecutive positive numbers is 61.?
Let the two consecutive positive numbers be ( n ) and ( n+1 ). The equation can be set up as ( n^2 + (n+1)^2 = 61 ). Expanding this gives ( n^2 + n^2 + 2n + 1 = 61 ), which simplifies to ( 2n^2 + 2n - 60 = 0 ). Dividing by 2, we have ( n^2 + n - 30 = 0 ), which factors to ( (n-5)(n+6) = 0 ), yielding ( n = 5 ) (since ( n ) must be positive). Thus, the consecutive numbers are 5 and 6.
