Two numbers have a product of 108 and a quotient of 3 What are the numbers?

Answer 1

xy = 108

x/y = 3

x = 3y

xy = 108

(3y)y = 108

3y2 = 108

y2 = 36

y = +&- 6

Thus the pair of numbers are 18 and 6 or -18 and -6.

Check.

Answer 2

Oh, isn't that just a happy little math problem? Let's see, if the product of two numbers is 108 and their quotient is 3, we can think of those numbers as x and y. So, x * y = 108 and x / y = 3. By solving these equations, we find that the numbers are 9 and 12. Just like painting a beautiful landscape, sometimes all it takes is a little patience and gentle brushstrokes to reveal the answer.

Answer 3

Let's denote the two numbers as x and y. We know that xy = 108 and x/y = 3. From the second equation, we can rewrite it as x = 3y. Substituting this into the first equation gives us 3y * y = 108, which simplifies to 3y^2 = 108. Solving for y, we find y = 6. Substituting y back into x = 3y gives us x = 18. Therefore, the two numbers are 18 and 6.