For the tens digit to be a Prime number then it must equal 2, 3, 5 or 7.
There are four 3-digit prime numbers that fit the above condition and also have the tens and units digits forming a 2-digit prime number.
131, 137, 173, 179. The person supplying the question may like to sum the various combinations.
The ratio of the number of one-digit prime numbers to the number of one-digit composite numbers is one to one. The one-digit prime numbers are 2, 3, 5, and 7. The one-digit composite numbers are 4, 6, 8, and 9. Therefor, the ratio is 4:4, which simplifies to 1:1.
11 is the smallest 2-digit prime number and 97 is the greatest 2 digit prime number, so their difference is 86
There are four of each.
There are 900 three-digit whole numbers between 1 and 1000
there are 50 prime numbers between 1-100 and of them 2,3,5,7 are single digit so that would leave 46 double digit prime numbers between 1-100
Yes.
Since both of those numbers contains four digits, there are no three-digit numbers between them.
If you include the number 3,000, there are exactly 2,001 4-digit numbers between 500 and 3000.
The diference between the highest 4 digit number and the lowest 3 digit number is 9999 Highest 4 digit: 9999 Lowest 3 digit: 000
By including the number 1000, the digit 1.
9888
20 101 a three digit number and i don't know what is the answer
Greatest 2 digit Prime number is 97. Lease 2 digit prime number is 11.
Greatest 2 digit prime number is 97. Lease 2 digit prime number is 11.
There are 17 such numbers.
4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.
It is a number with two digits in it. So it goes into the "tens" place of the numbers. Basically any whole number from 10 to 99. See how any number between those numbers only has 2 numbers, or digits that make up the number? 9 would only be a single-digit number, and 100 would be a triple-digit number.