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let x = 1st number, then 19 - x = 2nd number 120 = x(19 - x) x2 -19x +120 = 0 use quadratic formula to solve x = (19 +/- sq rt(361 - 480))/2 x = (19 + sq root (-119))/2 or x = (19 - sq root (-119))/2 '''x = 19/2 + ''i''(sq rt 119) /2 and''' '''x = 19/2 - ''i''(sq rt 119) /2''' there are no real solutions, both are imaginary. Actually they are complex conjugates.

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Q: What 2 factors of 120 can be added together to equal 19?
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