111,111 = 3 x 7 x 11 x 13 x 37. (3,7,11,13,37).
111111 = 3 * 7 * 11 * 13 * 37
The product of two prime numbers can never be another prime number, the numbers that you multiplied are factors of the product. (example, 9 times 5 is 45, 9 and 5 go into 45)
15 is the product of two prime numbers; 3 x 5
As a product of its prime factors: 2*2*3*3*5*5*5 = 4500
175 = 5 × 5 × 7
111111 = 3 * 7 * 11 * 13 * 37
prime numbers of 145 = 5, 29the product of 5 and 29 = 145
As a product of its prime numbers: 5*5*5 = 125
No, the product of 2 prime numbers is not always even. If one of the prime numbers is 2, then the product will be even. However, if both prime numbers are odd, then the product will be odd.
The product of two prime numbers can never be another prime number, the numbers that you multiplied are factors of the product. (example, 9 times 5 is 45, 9 and 5 go into 45)
the first thing to do is to is to narrow your options. There are a few things you know. The numbers that it cannot be: 1 (if it was one, it'd be 4 numbers instead of 5) 2 (isn't even) 5 (doesn't end in 5 or 0) #>111111 We know that it is the product of five numbers so we can deduce that it is likely that: 111111^(1/5) = ~ 10 (the numbers will proably be around 10): 7, 11, 13, Since the digits add up to 6 (which is a multiple of 3), one of the factors must be 3 So from there it's trial and error: 111111/3 =37037 Try 7 37037/7=5291 Try 11 5291/11=481 Try 13 481/13=37 So the numbers are: 3,7,11,13,37
15 is the product of two prime numbers; 3 x 5
As a product of its prime factors: 2*2*3*3*5*5*5 = 4500
As a product of its prime factors: 3*5*5 = 75
The product of the prime numbers 3 and 5 is 15.
70 written as a product of prime numbers: 2 x 5 x 7
No. 15 is the product of two prime numbers: 3 and 5