111111 = 3 * 7 * 11 * 13 * 37
The product of two prime numbers can never be another prime number, the numbers that you multiplied are factors of the product. (example, 9 times 5 is 45, 9 and 5 go into 45)
15 is the product of two prime numbers; 3 x 5
As a product of its prime factors: 2*2*3*3*5*5*5 = 4500
175 = 5 × 5 × 7
111111 = 3 * 7 * 11 * 13 * 37
prime numbers of 145 = 5, 29the product of 5 and 29 = 145
As a product of its prime numbers: 5*5*5 = 125
Both 3 and 5 are prime numbers. 3 x 5 = 15
The product of two prime numbers can never be another prime number, the numbers that you multiplied are factors of the product. (example, 9 times 5 is 45, 9 and 5 go into 45)
the first thing to do is to is to narrow your options. There are a few things you know. The numbers that it cannot be: 1 (if it was one, it'd be 4 numbers instead of 5) 2 (isn't even) 5 (doesn't end in 5 or 0) #>111111 We know that it is the product of five numbers so we can deduce that it is likely that: 111111^(1/5) = ~ 10 (the numbers will proably be around 10): 7, 11, 13, Since the digits add up to 6 (which is a multiple of 3), one of the factors must be 3 So from there it's trial and error: 111111/3 =37037 Try 7 37037/7=5291 Try 11 5291/11=481 Try 13 481/13=37 So the numbers are: 3,7,11,13,37
15 is the product of two prime numbers; 3 x 5
As a product of its prime factors: 2*2*3*3*5*5*5 = 4500
As a product of its prime factors: 3*5*5 = 75
The product of the prime numbers 3 and 5 is 15.
70 written as a product of prime numbers: 2 x 5 x 7
No. 15 is the product of two prime numbers: 3 and 5