The factors of 13 are 1 and 13. They do not total 11.
65 has 13 as a factor because 13 divides into 65 evenly with no remainder. The sum of the digits of 65 is 11 because 6 + 5 = 11
143 11, 13
False - 2 + 11 = 13.
13 and 5 11 and 7
11, 13 and 17.
2 and 11
65 has 13 as a factor because 13 divides into 65 evenly with no remainder. The sum of the digits of 65 is 11 because 6 + 5 = 11
65
65
65
65
No integer fits those conditions.
13 and 7
13
11 + 13 + 17 = 41
2n+13
sum = 48