First you should list all the factors of 60:
1,2,3,4,5,6,10,12,15,20,30
Now we can go through each of the factors and see if we can get another factor to add to 17 with it:
For 1 , we would need another factor of 16, which we don't have.
Trying 2, we would need 15, which IS a factor. So 2 and 15 would work.
2 and 15 5 and 12
66
All of the [positive] whole-number factors of 24 are: 1, 2, 3, 4, 6, 8, 12, and 24. Their sum is 60.
The sum of the first 60 positive integers is 1830.
30 and 60
2 and 15 5 and 12
43
-43
The sum is 144 if 60 is included, 84 if not.
60
12 and 5 are the numbers. 12 + 5 = 17 and 12 x 5 = 60Think of the factors first.1,602,303,204,155,12 We've got a winner!!!6,10
To find two numbers that sum to 17 and have a product of 60, we can set up the equations (x + y = 17) and (xy = 60). By expressing (y) in terms of (x) (i.e., (y = 17 - x)) and substituting into the product equation, we get (x(17 - x) = 60). This simplifies to the quadratic equation (x^2 - 17x + 60 = 0). Solving this yields the numbers 12 and 5, since (12 + 5 = 17) and (12 \times 5 = 60).
12
36 and 24
1 and 2.
The factors of -60 that add up to 17 are 20 and -3. When you multiply 20 and -3, you get -60, and when you add them together, you get 17. Therefore, the pair of factors you are looking for is 20 and -3.
28