36 x 1
18 x 2
Because all of them divide evenly into 36 with no remainder.
The result of 36 multiplied by anything, is a multiple of 36. For example, 1 X 36=36, 2 X 36=72, 3 X 36=108, so 36, 72, 108 etc... are all multiples.
All multiples of 36 are multiples of 18.
It is (17+55)/2 = 36
Yes they are all factors of 36
One efficient way to find the median of k sorted arrays is to merge all the arrays into one sorted array and then find the middle element. This method has a time complexity of O(n log k), where n is the total number of elements in all arrays and k is the number of arrays.
I assume you mean that you have a number of rows, and that not all rows have the same number of "cells". Yes, in Java a two-dimensional array is implemented as an array of arrays (each item in the top-level array is, in itself, an array); a 3-dimensional array is an array of arrays of arrays, etc.; and there is no rule stating that all secondary (etc.) arrays must have the same number of elements.
The median of two sorted arrays is the middle value when all the numbers are combined and arranged in ascending order.
Arrays having more than one dimension is known as multi-dimensional arrays. Multi-dimensional arrays is also known as arrays-of-arrays.
Arrays having more than one dimension is known as multi-dimensional arrays. Multi-dimensional arrays is also known as arrays-of-arrays.
You cannot sort arrays by other arrays; that wouldn't make sense, anyway.
Arrays are reported to be omnivoire.
1*39 and 3*13.
No, but factors can.
for arrays you can list the different arrays and what attributes that you give to them.
Arrays whose size can be altered are known as dynamic arrays.
Arrays can be of following types.