It is (17+55)/2 = 36
The sum of the first ten positive integers is: 55
The sum of the first ten positive integers, i.e. 1,2,3,4,5,6,7,8,9, and 10, is 55. The sum of the first ten negative integers, i.e. -1,-2,-3,-4,-5,-6,-7,-8,-9, and -10 is -55. The sum of the first ten positive integers plus the sum of the first ten negative integers is 0.
Sum of first n integers is n/2 times n + 1 ie 27.5 x 56 which is 1540
Call the small number X and the larger one X+1. Sum of the first and three times the second is 55: X + 3(X+1) = 55; simplify and solve for X: X=13. So the integers are 13 and 14.
The easiest way to do this is to use 'n' as one integer. Now, the next one needs to be consecutive, so we can make the second integer 'n+1' n + (n+1) = 55 Now all we do is start simplifying 2n + 1 = 55 2n = 55 -1 2n = 54 n = 27 Since n = 27, the first integer will be 27. And we stated that the second is 'n+1', so the second would be 28. Double check, 27 + 28 = 55 So, our integers are 27 and 28.
The arithmetic mean is 36.
55
55 is between the integers 54 and 56
All of them from 45 to 99 ... 55 integers.
55
17% of 55= 17% * 55= 0.17 * 55= 9.35
The integers are 51, 53 and 55.
55
Well, I don't believe this is the answer, but 55 works. 55+55+55=165.
Assuming the question refers to INTEGERS and not numbers, the answer is 55.
55,-16,and-455
The integers are 51, 53, 55 and 57.