There is an infinite number of them.
Cubes of all numbers are irrational numbers, if they're not natural
Sixth powers.
Any "cube" has 6 faces, so you could have 6 different numbers, as on dice.
none 3 x 3 x 3 = 27 4 x 4 x 4 = 64 ---------------------------- Every number has a cube root, just most of them are not whole numbers, so every number between 30 and 50 is a cube. If you meant what the perfect cube numbers (ie the cubes of whole numbers) between 30 and 50, then the answer is, as above, none.
Those are the cubes of the numbers 1-10. Just calculate the cube of 1, the cube of 2, the cube of 3, etc., up to the cube of 10.
You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.You cannot. And not all number cubes have the numbers 1-6 on them. For example, a doubling cube for backgammon.
There is an infinite number of them.
101
All numbers have cube roots (not necessarily integral cube roots) so every prime has cube roots.
Just calculate the cube of 0, the cube of 1, the cube of 2, etc.
you multiply all numbers you see. If triangle you multiply all numbers then divide it by three
There are infinitely many of them and so it is not possible to list them.
Cubes of all numbers are irrational numbers, if they're not natural
Whatever it is, all three numbers are the same.
1, 8, and 27
1, 8, 27, 64