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2x112
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∙ 15y ago
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What is a factor tree for 242?
242 2 x 121 2 x (11x11) Since 2 and 11 are prime numbers, the factor tree is complete.
What are the factors and prime factors of 242?
The factors of 242 are 1, 2, 11, 22, 121, and 242. The factor pairs of 242 are 1 x 242, 2 x 121, and 11 x 22. The prime factors of 242 are 2, 11, and 11. The distinct prime factors of 242 are 2 and 11. The prime factorization of 242 is 2 x 11 x 11 or, in exponential form, 2 x 112.
What number is relativly prime to 242?
15 is relatively prime.
Are any two prime numbers relatively prime?
Any two prime numbers will be relatively prime. Numbers are relatively prime if they do not have any prime factors in common. Prime numbers have only themselves as prime factors, so all prime numbers are relatively prime to the others.
What two numbers multiply to make 242?
1 x 242, 2 x 121, 11 x 22
How do you get 242 using prime numbers?
2 x 11 x 11 = 242
What equals 242 using prime numbers?
2 x 11 x 11 = 242
Is 242 a prime number?
No. Any even numbers (numbers ending in 2, 4, 6, 8, or 0) are even, and all even numbers are divisible by 2; eg. 242 / 2 = 121 - not prime.
Is 242 prime or composite?
242 is a composite number.Prime numbers have only two factors - 1 and the number itself.There are many other numbers that can be divided into 242, making it a composite number.
What are the prime factors of 242?
The prime factors of 242 are: 2 and 11
What is a factor tree for 242?
242 2 x 121 2 x (11x11) Since 2 and 11 are prime numbers, the factor tree is complete.
What are the factors and prime factors of 242?
The factors of 242 are 1, 2, 11, 22, 121, and 242. The factor pairs of 242 are 1 x 242, 2 x 121, and 11 x 22. The prime factors of 242 are 2, 11, and 11. The distinct prime factors of 242 are 2 and 11. The prime factorization of 242 is 2 x 11 x 11 or, in exponential form, 2 x 112.
What are the prime factors for 242?
The prime factors are: 2,11
Prime Factorization of 242?
2 x 11 x 11 = 242
What number is relativly prime to 242?
15 is relatively prime.
What are palindromic numbers that are prime numbers between 200 and 300?
202, 212, 222, 232, 242, 252, 262, 272, 282, and 292 are the palindromic numbers between 200 and 300. NONE of them are prime, since they must all end in 2 they are even and so are divisible by 2, so they are not prime.
How you write 242 in prime factorization usin exponents?
242 = 21 x 112
