41
The consecutive odd integers for 114 are 37, 38 and 39.
The numbers are: 378 and 42 because (9*42)*42 = 15876
It is: 2*3*7 = 42
42 = 2 * 3 * 7the prime factors of 42 are 1,2,3,7the product of these numbers is... 1x2x3x7 = 42
This is impossible to achieve with integers. If the numbers are consecutive even numbers, then this is the solution: 42 + 62 = 16 + 36 = 52
No.
Three consecutive odd numbers: 3, 5, 7
The sum of the first 60 consecutive odd numbers is 3,600.
21, 23, 25, and 27
23+21+19+17=80
63, 65, 67, 69 = 264 so there does not appear to be a solution in whole numbers!
No 7 consecutive numbers will total 38. If you meant 28, then it would just be 1 through 7.
If you had tried the first such set you would have seen that the answer is no. 1+2+3+4 = 10 which is not divisible by 4.
The LCM is 42.
Write them in a column. Since there is only one number per row, there is no chance of consecutive numbers being in the same row.
The numbers are: 80 and 4