(75,1)(25,3)(15,5)
The factor pairs of 150 are 1*150, 2*75, 3*50, 5*30, 6*25, and 10*15
You find a factor pair take the number that you want to find the factor pair of and divide it by a number. If the answer come out evenly then that's your factor pair EX. Factor pairs of 150 1 and 150 2 and 75 3 and 50 5 and 30 6 and 25 10 and 15
The factor pairs of 57 are 3x19 and 1x57
The factor pairs of 343 are (343,1) and (49,7)
There are three factor pairs for 75:factor pair = 75,1factor pair = 25,3factor pair = 15,5
(75,1)(25,3)(15,5)
(75,1)(25,3)(15,5)
1 & 75 3 & 25 5 & 15 are the factor pairs of 75.
The factor pairs of 150 are 1*150, 2*75, 3*50, 5*30, 6*25, and 10*15
The prime factors of 75 are 3,5,5 as 3*5*5=75. This can be determined by testing 75 for divisibility by prime numbers starting from 2. Using the prime factorization you can determine that all the factor pairs are (3*5)*5=15*5 and 3*(5*5)=3*25
1 x225 ,3x 75, 5x45,9x25,15x15 I think those are all of them
Yes. Factor pairs are always repeated across pairs since factor pairs are certain kinds of pairs.
You find a factor pair take the number that you want to find the factor pair of and divide it by a number. If the answer come out evenly then that's your factor pair EX. Factor pairs of 150 1 and 150 2 and 75 3 and 50 5 and 30 6 and 25 10 and 15
1 x 525, 3 x 175, 5 x 105, 7 x 75, 15 x 35, 21 x 25
the factor pairs are 1x35 & 5x7
The factor pairs of 28 are :28,114,27,4