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378 is a composite number because it has factors other than 1 and itself. It is not a Prime number.
The 16 factors of 378 are 1, 2, 3, 6, 7, 9, 14, 18, 21, 27, 42, 54, 63, 126, 189, and 378.
The factor pairs of 378 are 1 x 378, 2 x 189, 3 x 126, 6 x 63, 7 x 54, 9 x 42, 14 x 27, and 18 x 21.
The proper factors of 378 are 1, 2, 3, 6, 7, 9, 14, 18, 21, 27, 42, 54, 63, 126, and 189 or,
if the definition you are using excludes 1, they are 2, 3, 6, 7, 9, 14, 18, 21, 27, 42, 54, 63, 126, and 189.
The prime factors of 378 are 2, 3, 3, 3, and 7. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.
The 3 distinct prime factors (listing each prime factor only once) of 378 are 2, 3, and 7.
The prime factorization of 378 is 2 x 3 x 3 x 3 x 7 or, in index form (in other words, using exponents), 2 x 33 x 7.
NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.
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Can someone express 378 as a product of prime factors using the tree method?
378 189,2 63,3,2 21,3,3,2 7,3,3,3,2
How do you Express 378 as the product of prime factors?
2 x 3 x 3 x 3 x 7 = 378
What is the hcf of 126 196 378?
To find the highest common factor (HCF) of 126, 196, and 378, we first need to find the prime factors of each number. The prime factors of 126 are 2 x 3 x 3 x 7, the prime factors of 196 are 2 x 2 x 7 x 7, and the prime factors of 378 are 2 x 3 x 3 x 3 x 7. To find the HCF, we look for the common prime factors among the numbers, which are 2 and 7. Multiplying these common factors gives us the HCF, which is 14.
What is prime factorization of using exponents 378?
It is: 2*33*7 = 378
Factors of 378?
9*42
