37: 1, 37
38: 1, 2, 19, 38
39: 1, 3, 13, 39
40: 1, 2, 4, 5, 8, 10, 20, 40
41: 1, 41
42: 1, 2, 3, 6, 7, 14, 21, 42
43: 1, 43
44: 1, 2, 4, 11, 22, 44
45: 1, 3, 5, 9, 15, 45
46: 1, 2, 23, 46
47: 1, 47
48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
31: 1, 31 32: 1, 2, 4, 8, 16, 32 33: 1, 3, 11, 33 34: 1, 2, 17, 34 35: 1, 5, 7, 35 36: 1, 2, 3, 4, 6, 9, 12, 18, 36 37: 1, 37 38: 1, 2, 19, 38 39: 1, 3, 13, 39
The consecutive odd integers for 114 are 37, 38 and 39.
31, 37, and 41 are prime. All others are composite, i.e., one of their factors is a smaller number.
no, equivalent sets must have exactly the same elements.
30, 32, 33, 34, 35, 36, 38, 39, 40
The factors of 37 are: 1, 37 The factors of 38 are: 1, 2, 19, 38 The factors of 39 are: 1, 3, 13, 39 The factors of 40 are: 1, 2, 4, 5, 8, 10, 20, 40 The factors of 373839 are: 1, 3, 29, 87, 4297, 12891, 124613, 373839
It is 38, the middle number when they are arranged in order.
The numbers are 37, 38, 39 and 40.
37 - rubidium 38 - strontium 39 - yttrium 40 - zirconium 41 - niobium
36: 1, 2, 3, 4, 6, 9, 12, 18, 36 38: 1, 2, 19, 38 39: 1, 3, 13, 39 40: 1, 2, 4, 5, 8, 10, 20, 40
First ticket can be any of 40, second any of 39, third any of 38 and fourth any of 37 so 40 x 39 x 38 x 37 different ways which is 2,193,360.
31: 1, 31 32: 1, 2, 4, 8, 16, 32 33: 1, 3, 11, 33 34: 1, 2, 17, 34 35: 1, 5, 7, 35 36: 1, 2, 3, 4, 6, 9, 12, 18, 36 37: 1, 37 38: 1, 2, 19, 38 39: 1, 3, 13, 39
You can be 31, 32, 33, 34, 35, 36, 37, 38, and 39.
Common factors of 38 and 40 are 1 and 2.
The consecutive odd integers for 114 are 37, 38 and 39.
It is 37. It is 37. It is 37. It is 37.
you cannot anser with 40, it is 39