6x-6y=6(x-y) The factors of 6(x-y) are 6 and (x-y).
8x2 + 6x - 9 = 8x2 + 12x - 6x - 9 = 4x(2x + 3) - 3(2x + 3) = (2x + 3)(4x - 3)
The greatest common factor of 12xy2 + 6x is 6x. The greatest common factor of 12 and 6 is 6, and the greatest common factor of xy2 and x is x. If you took 6x out of both factors, the end result would be 2y2+1
You didn't bother to list the binomials to choose from, but the two binomial factors of x2 + 6x - 40 are (x + 10) and (x - 4)
The factors are -1(2x + 1)(3x + 4)
If that's 6x + 10, that factors to 2(3x + 5)
There is a formula for "the difference of squares." In this case, the answer is (6x + 11y)(6x - 11y)
(x^2 - 6x + 18)(x^2 + 6x + 18)
x2 + 6x - 27 = (x + 9)(x - 3)
What are the factors? 2x3 - 8x2 + 6x = 2x(x - 1)(x - 3).
x2-6x can be factored into x(x-6). Simply factor out the "x" from both factors.
6 is 6(x-1)
Assuming that the first operator is 6x^2. The factors are (6x-5)*(x-1)
6x-6y=6(x-y) The factors of 6(x-y) are 6 and (x-y).
x2 + 6x - 72 = (x + 12)(x - 6)
8x2 + 6x - 9 = 8x2 + 12x - 6x - 9 = 4x(2x + 3) - 3(2x + 3) = (2x + 3)(4x - 3)
6(x-1) 2x3(x-1)