The multiples of 18 are 18, 36, 54, 72, 90, 108, 126, 144, 162, 180, 198, and so on. There are an infinite number of multiples of 18.
They are the infinitely many numbers of the form 18*k where k is an integer.
18, 36, 54, 72, 90, 108, 126, 144, 162, 180, 198, 216, 234, 252, 270, 288, 306, 324, 342, 360
Multiply 18 by any integer, for example: 0x18, 1x18, 2x18, -1x18, etc.
Or start with 0, and add 18 at a time.
18 36 54 72 90 108 126 144 162 180 and so on
All multiples of 36 are multiples of 18.
The multiples of 18 in ascending order are 12345678
18, 36, 54, 72, and 90 = the first five multiples of 18
2, 6 and 18 are numbers that are multiples of 2 and factors of 18.2, 6 and 18
The first five positive integer multiples of 18 are as follows:1 x 18 = 182 x 18 = 363 x 18 = 544 x 18 = 725 x 18 = 90
All multiples of 36 are multiples of 18.
18 and all the multiples of 18.
The multiples of 18 in ascending order are 12345678
Multiples are just numbers that can be multiplied together to find the given number. So: Multiples of 9: 1,3,9 Multiples of 18: 1,2,3,6,9,18 Common Multiples of 9 & 18: 1,3,9
The set of multiples of 18.
The common multiples of 18 and 24 are 72 and 144.
18, 36, 54, 72, and 90 = the first five multiples of 18
3: 3, 6, 9, ... 6: 6, 12, 18, ... 18: 18, 36, 54, ... The lcm(3, 6, 18) = 18, so the multiples of 18 are common multiples of all of them.
Multiply 18 by a series of numbers. Therefore, multiples of 18 are, as follows: 18, 36, 54, 72, 90, 108...
it is 18. 18 is a multiple of all three numbers. multiples of 3: 3,6,9,12,15,18... multiples of 6: 6,12,18... multiples of 9: 9, 18...18
The question is asked incorrectly. "The" six multiples of 18 means there are only six multiples. 18 times any integer is a multiple of 18, thus: 18 x 0 = 0 18 x 1 = 18 18 x 2 = 36 18 x -1 = -18 etc. As you see, there are infinitely many multiples of 18, not just 6.
They are 180 and any of its multiples