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Q: What are the prime factors of 152?

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The prime factors of 152 are 2, 2, 2, and 19.

The prime factors of 152 are 2 x 2 x 2 x 19 or 23 x 19.

The positive integer factors of 152 are: 1, 2, 4, 8, 19, 38, 76 and 152.As a product of its prime factors: 2*2*2*19 = 152

no because a prime numbers only factors are one and its self.

152 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 8 factors of 152 are 1, 2, 4, 8, 19, 38, 76, and 152.The factor pairs of 152 are 1 x 152, 2 x 76, 4 x 38, and 8 x 19.The proper factors of 152 are 1, 2, 4, 8, 19, 38, and 76 or,if the definition you are using excludes 1, they are 2, 4, 8, 19, 38, and 76.The prime factors of 152 are 2, 2, 2, and 19. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The 2 distinct prime factors (listing each prime factor only once) of 152 are 2 and 19.The prime factorization of 152 is 2 x 2 x 2 x 19 or, in index form (in other words, using exponents), 23 x 19NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.

152 = 2 x 2 x 2 x 19

As a product of its prime factors: 2*2*2*19 = 152

prime factors for 304:(304) = 2 * (152)(152) = 2 * (76)(76) = 2 * (38)(38) = 2 * 19 (19 is prime so tree ends)so prime factors are: 2*2*2*2*19 = 304

2 x 2 x 2 x 19 = 152

2 x 2 x 2 x 19 = 152

The prime factors of 140 are 2, 2, 5, and 7. The prime factors of 124 are 2, 2, and 31. The prime factors of 152 are 2, 2, 2, and 19. The only common factors are 2 and 2. Include 1, and you find that the three numbers that will evenly go into 140, 124, and 152 are 1, 2, and 4.

If the two numbers have no factors in common then they are relatively prime. 152 = 2 x 2 x 2 x 19 171 = 3 x 3 x 19. They both have 19 as a factor and therefore 152 and 171 are NOT relatively prime.

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