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When you divide by a divisor q, the remainders can only be integers that are smaller than q. If the remainder is 0 then the decimal is terminating. Otherwise, it can only take the values 1, 2, 3, ... ,(q-1). So, after at most q-1 different remainders you must have a remainder which has appeared before. That is where the long division algorithm loops back into an earlier pattern = repeating sequence.
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What causes a repeating decimal in the long division?
When you divide by a divisor q, the remainders can only be integers that are smaller than q. If the remainder is 0 then the decimal is terminating. Otherwise, it can only take the values 1, 2, 3, ... ,(q-1). So, after at most q-1 different remainders you must have a remainder which has appeared before. That is where the long division algorithm loops back into an earlier pattern = repeating sequence.
How do you round 7.9?
Oh, dude, rounding 7.9 is like, so easy. You just look at the number after the decimal point, which is 9 in this case, and since it's greater than 5, you round up. So, 7.9 becomes 8. Boom, math wizardry at its finest!
Define the following?
One of the leading causes of blindness in the US, glaucoma results from a group of eye conditions which causes optic nerve damage due to abnormally high pressure inside the eye.
What are precipitating factors?
Basically "precipitating factors" are the causes of something.
How do you round 14.651 to the nearest tenth?
14.7 is the answer. The 51 at the end causes the 6 to round up to 7.
