improper fraction of 3 - 7 over 9 = 34/9 3 7/9:= [(9 * 3)+7]/9= [27+7]/9= 34/9 in improper fraction
63
1, 3, 7, 9, 21, 63.
7 8 and 9 go into evenly in the multiples of 504.Multiples of 504 are 504, 1008, 1512, ...prime factorization of:7 =.... 78 = .........2 x 2 x 29 = .........................3 x 3=================LCM= 7 x 2 x 2 x 2 x 3 x 3 = 504
answer: 1 explain: (no explain found)
multiples of 63
It Is: 63
9 goes to 27= 3 times9 * 3 = 27
They can go into 63 and all its multiples.
7 can go into 66 9 times with the remainder of three. 7 x 9 = 63 remainder 3
63 and its multiples
9 R 3
8 times with a remainder of 1
9 go into 63 7 times
only 1 and 7 can go into 7 evenly.. but 9 and 3 go into 27 evenly
7 r.3/ remainder of 3
The factors of 7 are 1 and 7. The factors of 9 are 1,3,and 9. The factors of 6 are 1,2,3,and,6.This was by a 10 year old.