Any element of the set of numbers of the form 24*k, where k is an integer, is evenly divisible.
Any multiple of 24.
1, 2, 3, 6 1, 7 1, 2, 4, 8
8:6=1:3/4 6:8=1:1&1/3
9
The GCF of 3, 6, and 8 is 1
The greatest common factor of 6 and 8 is 2. 6/8 = (3×2)/(4×2) = 3/4
8
24
6 with remainder 3.
48
8 with remainder 6.
Well you put them in order from least to greatest first 3 3 6 8 then you go to the middle well it shows 3 and six so now you go between 3 and six and get five get it?
How many times does seven go into fifty nine
It would be 16. The sequence is doubling pairs. 3 and 4 go on to be 6 and 8. 6 and 8 would go on to be 12 and 16. 12 and 16 would go on to be 24 and 32, and so on.
8.5
51 divided by 8= 6.375 (or 6 and 3/8).
1, 2, 3, 6 1, 7 1, 2, 4, 8
3 R 6