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(4x + 3y)(4x + 3y) or (4x + 3y)2
3y=4x+9.....-4xAnswer: 4x-3y=9
16x2 + 8x + 1 - 9y2 = (4x + 1)2 - (3y)2 which is a difference of two squares. = (4x + 1 + 3y)*(4x + 1 - 3y)
It is: -3(4x-0.50) = -12x+1.50 or as 1.50-12x
12xy(3y - 4x)