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Let f = 0.161616...Then 100*f = 16.161616...

Subtracting the first from the second gives 99*f = 16

So that f = 16/99.


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Q: What is 0.16 repeating as a fraction in simplest form?
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0.016 as a fraction in simplest form?

.016 in fraction form is 2/125! Hope I could help!


How do you convert the decimal 0.16 into a fraction?

For any decimal , look at the number of decimal digits. Two(2) is this case. So we write it as over 1.00 (Note there are two decimal zeroes. Hence 0.16/1.00 Cancel down th4 decimal point 016/100 Ignore the prefix zero to '016. Hene 16/100 Since both numbers have a factor of '4' reduced/(Cancel down ) by '4'. Hence 16/100 = 4 /25 The Answer. As hinted above, for any decimal to be converted to a fraction , inspect the number of decimal places, and write the decimal number over one and the given number of decimal placed zeroes. . Then cancel down (reduce). Infinite decimals and irrational decimals require different technique.


Amy earns 016 per unit for the work she does For all units she produces in a week over 1000 she receives 0.26 What were her weekly earnings if she produced 1725 units in one week?

is that meant to be 0.16 per unit? assuming so, then the answer is: For the first 1000 she earns 0.16 per unit = 1000 * 0.16 = 160 Over 1000 she made 1725-1000=725. So she earns 0.26 for 725 units = 725 * 0.26 = 188.50 Add the two amounts together = 160 + 188.50 = 348.5 If you want to write this without all the workings it would be (1000*0.16)+(725*0.26)=348.5


What is the product of the first 100 prime numbers?

I think I did it right. Not sure what good this is, what purpose it could serve, but here it is: 11 356 769 871 639 834 366 628 078 343 660 801 213 021 002 603 808 017 113 484 083 456 481 393 624 183 355 161 423 988 601 739 578 097 269 175 036 999 016 380 044 894 643 879 365 114 584 536 377 648 421 251 919 478 851 653 433 974 523 196 310 641 702 368 516 916 764 541 545 146 381 989 396 087 448 510


How do you factor out 16x to the fourth power minus 81?

The answer below does find one root, and finding roots is one way to discover factors. But it does not find the complete factorization. x = -3/2 is also a root of the stated 'equation'. So two of the factors are (2x - 3) and (2x + 3). Then long division could be used to find remaining factor(s).Recall that a2 - b2 = (a + b)(a - b). Let a2 = 16x4, and b2 = 81.so, a = 4x2 and b = 9.So: 16x4 - 81 = (4x2 + 9)(4x2 - 9), and (4x2 - 9) factors to (2x + 3)(2x - 3).So the factorization is: (4x2 + 9)(2x + 3)(2x - 3).With complex: (2x + 3i)(2x - 3i)(2x + 3)(2x - 3), where i = sqrt(-1)So the other two roots are: 3i/2 and -3i/2Finding a root:16X^4 - 81 = 0add 81 to each side : 16X^4 = 81divide both sides by 16, leave as fractionX^4 = 81/16take 4th root both sidesX = 4root(81/16)this can be expressed as.........X = 4root(81)/4root(16)X = 3/2 [indicates (2x - 3) is one of the factors]check16(3/2)^4 - 81 = 016 * 81/16 - 81 = 00 = 0checks