As a product of its prime factors: 3*3*5*5*7 = 1575
To find the highest common factor (HCF) of 441 and 1575, we need to factorize both numbers. The prime factorization of 441 is 3^2 x 7^2, and the prime factorization of 1575 is 3^2 x 5^2 x 7. To find the HCF, we take the product of the common prime factors raised to the lowest power they appear in both factorizations, which is 3^2 x 7 = 63. Therefore, the highest common factor of 441 and 1575 is 63.
The GCF is 175.
write the number 14as a product of prime factor?
3 x 3 x 5 x 5 x 7 = 1,575
As a product of its prime factors: 3*3*5*5*7 = 1575
The GCF is 175.
What is the product of th e prime factor 344
No. By definition, the product has a proper factor - the prime.
Since 35 is a factor of 1575, it is automatically the GCF.
1 is not prime, so it can't be a prime factor.
3 x 3 x 5 x 5 x 7
express 5610 as the product of prime factors
47 as a product of prime factors is: 47. [47 is a prime number, so it only has itself as a prime factor - note 1 is NOT a prime number.]
Since 315 is a factor of 1575, it is automatically the GCF of this problem.
1,3,5,7,9,15,21,25,35,45,63,75,105,175,225,315,525,1575
1575 = 32 x 52 x 7