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What are the factors and prime factors of 236?
The factors of 236 are 1, 2, 4, 59, 118, and 236.The factor pairs of 236 are 1 x 236, 2 x 118, and 4 x 59.The proper factors of 236 are 1, 2, 4, 59, and 118 or,if the definition you are using excludes 1, they are 2, 4, 59, and 118.The prime factors of 236 are 2, 2, and 59. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The distinct prime factors of 236 are 2 and 59.The prime factorization of 236 is 2 x 2 x 59 or, in exponential form, 22 x 59.
How do you work out the product of prime factors?
Multiply prime numbers or prime factors to find their product.
How do you write 1375 as a product of prime factors?
As a product of its prime factors: 5*5*5*11 = 1375
What is 21 as a product of its prime factors?
21 as a product of its prime factors is 1 X 3 X 7.
How do you write 250 as a product of prime factors?
As a product of its prime factors: 2*5*5*5 = 250
