It is: 2*2*59 = 236
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The factors of 236 are 1, 2, 4, 59, 118, and 236.The factor pairs of 236 are 1 x 236, 2 x 118, and 4 x 59.The proper factors of 236 are 1, 2, 4, 59, and 118 or,if the definition you are using excludes 1, they are 2, 4, 59, and 118.The prime factors of 236 are 2, 2, and 59. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The distinct prime factors of 236 are 2 and 59.The prime factorization of 236 is 2 x 2 x 59 or, in exponential form, 22 x 59.
Multiply prime numbers or prime factors to find their product.
21 as a product of its prime factors is 1 X 3 X 7.
As a product of its prime factors: 2*5*5*5 = 250
As a product of its prime factors: 2*2*2*5*7 = 280