As a product of its prime factors: 2*3*5 = 30
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The product of the first three prime numbers (2, 3, and 5) is 30.
The prime factorization of 150 is 2 * 3 * 5^2. The distinct prime factors are 2, 3, and 5. To find the product of these distinct prime factors, you simply multiply them together: 2 * 3 * 5 = 30. Therefore, the product of the distinct prime factors of 150 is 30.
How about: 2*3*5 = 30 as a product of its prime factors
You factor the number into prime factors, dividing each prime out.
2 x 3 x 5 = 30