Their highest common factor is 105. Divide both by that and you get 3 over 7.
It is: 1050 -30% => 1050 -315 = 735
105, 210, 315, 420, and 525 have 3, 5 and 7 as prime factors. 105, 315, 525, 735 and 1575 have 3, 5 and 7 as their only prime factors.
735
735 rounded to the nearest ten is 740
The highest common factor (HCF) of two numbers is the largest positive integer that divides both numbers without leaving a remainder. To find the HCF of 735 and 630, we first list the factors of each number: 735 (1, 3, 5, 7, 15, 21, 35, 49, 105, 147, 245, 735) and 630 (1, 2, 3, 5, 6, 7, 9, 10, 14, 15, 18, 21, 30, 35, 42, 45, 63, 70, 90, 105, 126, 210, 315, 630). The highest common factor of 735 and 630 is 105.
735 over 1000 reduced is 147/200
105.
The GCF is: 105
The gcf is 105
It is: 1050 -30% => 1050 -315 = 735
105, 210, 315, 420, 525, 630, 735, 840, 945 . . .
105, 210, 315, 420, 525, 630, 735 +105 . . .
735 over 1
It is: 3*5*7^2 = 735
The list is infinite. Here are some of them: 210, 315, 420, 525, 630, 735, 840.
35/77 in simplest form is 5/11divide top and bottom by 735/77 = 5/11
This is a slight twist to the normal find the GCF of two numbers. In this case as a remainder of 7 is required, subtracting 7 from each number and then finding the GCF of the resulting numbers will solve the problem: 742 - 7 = 735 1162 - 7 = 1155 GCF of 1155 and 735 (using Euclid's method): 1155 / 735 = 1 r 420 735 / 420 = 1 r 315 420 / 315 = 1 r 105 315 / 105 = 3 r 0 GCF of 735 & 1155 is 105, thus 105 is the greatest number that will divide 742 and 1162 leaving a remainder of exactly 7 each time.