It is: 1050 -30% => 1050 -315 = 735
105, 210, 315, 420, and 525 have 3, 5 and 7 as prime factors. 105, 315, 525, 735 and 1575 have 3, 5 and 7 as their only prime factors.
735
735 rounded to the nearest ten is 740
HCF of 735 and 1050 is 105.
735 over 1000 reduced is 147/200
105.
The GCF is: 105
The gcf is 105
It is: 1050 -30% => 1050 -315 = 735
105, 210, 315, 420, 525, 630, 735, 840, 945 . . .
105, 210, 315, 420, 525, 630, 735 +105 . . .
735 over 1
It is: 3*5*7^2 = 735
The list is infinite. Here are some of them: 210, 315, 420, 525, 630, 735, 840.
35/77 in simplest form is 5/11divide top and bottom by 735/77 = 5/11
This is a slight twist to the normal find the GCF of two numbers. In this case as a remainder of 7 is required, subtracting 7 from each number and then finding the GCF of the resulting numbers will solve the problem: 742 - 7 = 735 1162 - 7 = 1155 GCF of 1155 and 735 (using Euclid's method): 1155 / 735 = 1 r 420 735 / 420 = 1 r 315 420 / 315 = 1 r 105 315 / 105 = 3 r 0 GCF of 735 & 1155 is 105, thus 105 is the greatest number that will divide 742 and 1162 leaving a remainder of exactly 7 each time.