0
50%
% rate:
= 5730/11460 * 100%
= 0.5 * 100%
= 50%
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∙ 11y ago
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The half-life of C14 is 5730 years. What fraction of the original C14 would you expect to be present in a fossil that is 28650 years old?
There would be 1/32 left.
What is 30 percent of 20 percent of 150 percent?
30 percent of 20 percent of 150 percent = 0.09
Is 0.900 percent equal to 90 percent?
0.900 percent = 0.90 percent = 0.9 percent = 9/10 percent 0.900 percent = 0.009 0.900 = 90 percent
How do you find a percent of a percent?
1 percent of a percent is 1/10000 or 0.0001; this is the same as saying 1 percent percent. Example: 5 percent percent is 0.0005, so 5 percent percent of 100 is 0.0005 x 100 or 0.05.
What percent of 10 percent of 50 is 25 percent of 100?
Parsing the question: What percent of 10 percent of 50 is 25 percent of 100? What percent of 10 percent of 50 is 25? What percent of 5 is 25? Answer: 500%
What is 57.3 as a percent?
5730%
The half-life is C-14 is 5730 years if a skeleton is found within 25 percent of the level it occurs at today how old is the skeleton?
5730/25% = 5730/0.25 = 22,920 years
Carbon 14 has a half life of 5730 In a plant fossil you find that this has decayed to a quarter of the original amount How long ago was this plant alive?
2 Half-Lifes= 1/4 Carbon 14 remaining. So 2 half lives have past. You add the 5730 years together to get 11460 years or 1.15*10^4 years.
What are the release dates for Days of Our Lives - 1965 1-11460?
Days of Our Lives - 1965 1-11460 was released on: USA: 15 November 2010
The half-life of carbon-14 is 5730 years After 11460 years how much of the original carbon-14 remains?
Since the radioactive decay of 14C is first order, one can use the equation offraction remaining = 0.5^n where n is the number of half lives. 28650yr/5730 yr = 5 half lives. Thus..fraction remaining = 0.5^5 = 0.03125 or 3.125% would be remaining.
What is 5730 divided by 100?
57.3
What is one fourth of 5730?
1/4 of 5730 = 1432.5
How do you write 5730 in exponential notation?
5730 in exponential notation is 5.73 x 10^3
What is the half life of an Egyptian papyrus with 63 percent of its original carbon-14 atoms?
The question is improperly asked. Papyrus does not have a half-life. Carbon-14 does. Half-life is constant, not variable, in this case, about 5730 years.So, the question would be more properly asked as "what is the age of an Egyptian papyrus with 63 percent of its original carbon-14 atoms?"The equation for radioactive decay is...AT = A0 2(-T/H)... where A0 is the starting activity, AT is the activity at some time T, and H is the half-life, in units of T.Substituting what we know, we get...0.63 = (1) 2(-T/5730)Solve for T...log2(0.63) = -T/5730T = -log2(0.63)(5730)T = 3819 (conservatively rounded, T = 3800)
The half-life of carbon-14 is 5730 years. How long will it take for the number of carbon-14 nuclei in a sample to drop to a quarter of the original number?
5370 years. A half-life is how long a radioactive object takes for half of all its atoms to become new elements. 100 is half of 200 =)
What is the refresh code of Nokia 5730?
*0000#
5730+53 its divide?
ok
