There would be 1/32 left.
30 percent of 20 percent of 150 percent = 0.09
0.900 percent = 0.90 percent = 0.9 percent = 9/10 percent 0.900 percent = 0.009 0.900 = 90 percent
1 percent of a percent is 1/10000 or 0.0001; this is the same as saying 1 percent percent. Example: 5 percent percent is 0.0005, so 5 percent percent of 100 is 0.0005 x 100 or 0.05.
Parsing the question: What percent of 10 percent of 50 is 25 percent of 100? What percent of 10 percent of 50 is 25? What percent of 5 is 25? Answer: 500%
5730%
5730/25% = 5730/0.25 = 22,920 years
It will take two half-lives for the number of carbon-14 nuclei to drop to a quarter of the original number. Since the half-life of carbon-14 is 5730 years, it will take 2 * 5730 years = 11460 years for this to occur.
Since the radioactive decay of 14C is first order, one can use the equation offraction remaining = 0.5^n where n is the number of half lives. 28650yr/5730 yr = 5 half lives. Thus..fraction remaining = 0.5^5 = 0.03125 or 3.125% would be remaining.
2 Half-Lifes= 1/4 Carbon 14 remaining. So 2 half lives have past. You add the 5730 years together to get 11460 years or 1.15*10^4 years.
Days of Our Lives - 1965 1-11460 was released on: USA: 15 November 2010
1/4 of 5730 = 1432.5
5730 in exponential notation is 5.73 x 10^3
57.3
The question is improperly asked. Papyrus does not have a half-life. Carbon-14 does. Half-life is constant, not variable, in this case, about 5730 years.So, the question would be more properly asked as "what is the age of an Egyptian papyrus with 63 percent of its original carbon-14 atoms?"The equation for radioactive decay is...AT = A0 2(-T/H)... where A0 is the starting activity, AT is the activity at some time T, and H is the half-life, in units of T.Substituting what we know, we get...0.63 = (1) 2(-T/5730)Solve for T...log2(0.63) = -T/5730T = -log2(0.63)(5730)T = 3819 (conservatively rounded, T = 3800)
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