580.0 × 10-9m written in standard notation is 0.0000005800m
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10^6
m-10<25
(m^5 - 10)(m^10 + 10m^5 + 100)
Let the two integers be m-1 & m, so the lesser integer is m-1, and the greater integer is m:(m-1) + 3*m = 43 --> 4*m -1 = 43 --> 4*m = 44, m = 11 & m-1 = 10, so 10 & 11Check: 11 times 3 is 33, add 10 is 43
m2 + 12m + 20 = ( m + 2)(m + 10)