10^6
m-10<25
(m^5 - 10)(m^10 + 10m^5 + 100)
Let the two integers be m-1 & m, so the lesser integer is m-1, and the greater integer is m:(m-1) + 3*m = 43 --> 4*m -1 = 43 --> 4*m = 44, m = 11 & m-1 = 10, so 10 & 11Check: 11 times 3 is 33, add 10 is 43
m2 + 12m + 20 = ( m + 2)(m + 10)
50
It is: m6 divided by m10 = m-4
580 centimeters is 5.8 meters.
Wave number is the reciprocal of the wavelength, so for a wavelength of 580 nm, the wave number would be calculated as 1 / 580 nm = 1.72 x 10^6 m^-1.
I believe the lake is at 580 m
5.8 meters=580 centimeters
METRIC PREFIXSCALE tera (T) 10 to th power of 12giga (G) 10 to th power of 9 mega (M) 10 to th power of 6 kilo (K) 10 to th power of 3 hecto (H) 10 to th power of 2 deca (da) 10 to th power of 1 BASIC UNIT 10 to the power of 0 deci (d) 10 to the pow of -1centi (c) 10 to the power of -2 milli (m) 10 to the power of -3 bwahahahaha studyfreakcollection
10^6
600,000m
58 meters=5,800 centimeters
n6c410800
The work done on the box is 3000 Joules (N*m) (300 N * 10 m). Power is work done per unit time, so the power applied to the box is 300 Watts (3000J / 10 s).