The LCM of 2, 5, 6 and 8 is 120.
The LCM of 2 and 8 is 8. Since 8 is a multiple of 2, it is automatically the LCM. To find the LCM of two numbers, list the multiples of each. 2: 2, 4, 6, 8, 10, 12 8: 8, 16, 24 Once you have a multiple that is common to both, you have found the LCM. In this case, the LCM is 8.
lcm(2, 3, 4, 5, 6, 7, 8) = 840
280
To find the smallest number that has 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 as factors, you need to find the least common multiple (LCM) of these numbers. The LCM is the smallest number that is divisible by all the given numbers. The LCM of 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 is 2520. Therefore, 2520 is the smallest number that has 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 as factors.
The LCM of 2 & 5, I believe, is 10. 2 : 2, 4, 6, 8, 10 5 : 5, 10
LCM of 8, 10 & 12 = 120Prime factorization of:8 = 2 * 2 * 210=2............512=2 * 2 ........ * 3============LCM=2*2* 2 * 5 * 3 = 120
The LCM is 40.
The Least Common Multiple (LCM) of 5, 8, and 10 is 40.
280
Prime factors of 8 are 23 Prime factors of 10 are 2 x 5 The LCM is the product of all the primes to their greatest power, so the LCM of 8 and 10 is 23 x 5 = 8 x 5 = 40
LCM of 5 10 12 8 is 120.
The LCM is: 120
To find the Least Common Multiple (LCM) of 4, 5, 8, and 10, we first need to find the prime factorization of each number. The prime factorization of 4 is 2^2, 5 is a prime number, 8 is 2^3, and 10 is 2 * 5. Then, we take the highest power of each prime factor that appears in any of the numbers: 2^3 * 5 = 40. Therefore, the LCM of 4, 5, 8, and 10 is 40.
lcm(7, 10, 8, 49, 70) = 1960 7 = 7 10 = 2 x 5 8 = 2^3 49 = 7^2 70 = 2 x 5 x 7 lcm = 2^3 x 5 x 7^2 = 1960
360. 18 = 2 x 32 8 = 23 10 = 2 x 5 lcm = 23 x 32 x 5 = 360
Factor them. 2 x 2 x 2 = 8 2 x 5 = 10 Combine the factors, eliminating duplicates. 2 x 2 x 2 x 5 = 40, the LCM