3 x 7 = 21
The prime factorization of 21 can be expressed as 3^1 * 7^1, where 3 and 7 are both prime numbers. This means that 21 can be broken down into the product of these prime factors raised to their respective exponents. In other words, 21 is the result of multiplying 3 by 7.
(98) = 2 * (49) = 7 * 7 ( both primes, end sequence) so > prime factors are : 21 * 72
22 is 11 x 2 and both 11 and 2 are prime numbers. So we write the prime factorization as 2 x 11. Now the question asks for exponents, but it appears none are there. In fact, 11 can be also written as 111 and the same with 2. So you can write 22 = 111 x 21 . Most people don't write it this way, but it does tell you that there is one 11 and one 2 in the prime factorization.
The prime factorization for 21 is: 3x73 x 7 = 21
The prime factors of 90 in exponential form are 21 x 32 x 51.
The prime factorization of 50 using exponents is 21 x 52
3 x 7 = 21 No exponents necessary.
10 = 21*51
21 x 33
54 = 21 x 33
1250 = 21 x 54
18 = 21 x 32
It is: 21*71*111 = 154
21 x 831 = 166
14 = 21 x 71
94 = 21 x 471
302 = 21 x 1511