1, 5, 7, 35, 49, 245
The right answer is 5x5x17
As a product of its prime factors: 5*7*7 = 245
To find the highest common factor (HCF) of 245 and 140, we need to determine the largest number that divides both 245 and 140 without leaving a remainder. The factors of 245 are 1, 5, 7, 35, 49, and 245. The factors of 140 are 1, 2, 4, 5, 7, 10, 14, 20, 28, 35, 70, and 140. The common factors of 245 and 140 are 1, 5, and 35. Therefore, the highest common factor of 245 and 140 is 35.
As a product of its prime factors: 5*7*7 = 245
All factors of 245: 1, 5, 7, 35, 49, 245.
sum of prime factors of 245 = 12factors of 245: 1, 5, 7, 35, 49, 245.prime factors of 245: 5 & 7sum of prime factors of 245: 5 + 7 = 12
1, 5, 7, 35, 49, 245 -1, -5, -7, -35, -49, -245
1, 5, 7, 35, 49, 245
5 and 7 are the prime factors of 245.They are: 5 and 7
As a product of its prime factors: 5*7*7 = 245
The factors of 245 are 1, 5, 7, 35, 49, and 245. The pairs are 1*245, 5*49, and 35*7. The prime factorization of 245 is 5*7*7 or in exponential form 5*72. The prime factors are 5 and 7.
5 and 7 5 x 7 x 7 = 245
1, 5, 7, 35, 49, 245
The answer to that is 5*7squared=245.
5 x 7 x 7 = 245
The right answer is 5x5x17