There are infinite numbers match to this description. For example: 11,111111.......(and so on), 11,22222..., 11,55555555....., 11,99999999... and many more I can't write here.
An irrational number is a number that never ends. An example of an irrational square root would be the square root of 11.
The same as you would a rational number. Its distance from zero will represent the number, whether it is rational or irrational.
Rational number can be divided into more that the number 2. Irrational number are numbers that can only be divided evenly with the number 2.
No; here's a counterexample to show that the set of irrational numbers is NOT closed under subtraction: pi - pi = 0. pi is an irrational number. If you subtract it from itself, you get zero, which is a rational number. Closure would require that the difference(answer) be an irrational number as well, which it isn't. Therefore the set of irrational numbers is NOT closed under subtraction.
Simply plot the irrational number at it's approximate location on the number line and label the irrational number. For example, if you were to plot pi on the number line, you would plot it at about 3.14 and label it with "π" (the pi symbol, if it doesn't show up) Another example is if you want to plot the square root of 2 on the number line. You would plot it at around 1.414 and label it with "√2"
There may be many easier and better ways, but here's how I would do it: -- Square the first given irrational number. -- Square the second irrational number. -- Pick a nice ugly complicated decimal between the two squares. -- Take the square root of the number you picked. It's definitely between the two given numbers, and it would be a miracle if it's not irrational.
There is no first irrational number. Irrational numbers are infinitely dense which means that there are infinitely many of them in any interval. So if any number laid claim to being the first, there would be infinitely many that would be between 0 and that number. Each one of them would then have a better claim to be "first".
The answer will depend on the form in which the irrational number is given. For example, we know that pi is approx 3.14159 and so it falls between 3 and 4.
How would you do that ?? You'd have to change the value of the number. As long as the irrational number keeps its original value, it's an irrational number.
no. an example of an irrational number would be like the square root of 3
Pie is an irrational number because it has infinite decimal places.
Irrational numbers are infinitely dense. Between any two numbers, there are infinitely many irrational numbers. So if it was claimed that some irrational, x, was the closest irrational to 6, it is possible to find an infinite number of irrationals between 6 and x. Each one of these infinite number of irrationals would be closer to 6 than x. So the search for the nearest irrational must fail.
An example of a whole number would be this >>> 2 1/3 Except a real number would be any rational Or irrational number :)
To be irrational, it would have to have an infinite number of digits, without a periodic repetition.
I would say no, it is rational. A number is only irrational if it repeats with no specific pattern.
An irrational number is a number that never ends. An example of an irrational square root would be the square root of 11.
Yes - if I had an irrational number x, and I added that to the number (7-x), I would end up with 7.If the number is irrational, it can be subtracted from a rational/integer to make another irrational.