As we know that the formula of
n!=n(n-1)!
so 8!=8*(8-1)!
=8*7!
=8*7*6!
=8*7*6*5!
=8*7*6*5*4!
=8*7*6*5*4*3!
=8*7*6*5*4*3*2!
=8*7*6*5*4*3*2*1!
=8*7*6*5*4*3*2*1
=40320
so the factorial of the given no. 8 is 40320.
9 x 8! = 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1So, 9 x 8! = 9! = 362,800
x - 8
(x-8)(x+8) = x2-64
Great. A multiple choice question with no choices. Find the expression that equals 8.
It is: 3(n+8)
8! means 8*7*6*5*4*3*2*1=40,320
That's not the factorial of any number. For a start, the factorial of any number greater than or equal to 2 is even, because of the factor 2. The factorial of any number greater or equal to five ends with 0. Another answer: I suspect the questioner meant to ask how to write 8*7*6*5*4*3*2*1 as a factorial. If so, then the answer is "8!"
720
8!
40320
3! = 3×2×1 = 6
Regular expression is built in and the regular definition has to build from regular expression........
8
The regular expression for an integer is: -?d
2.5
9 factorial = 9! = (9*8*7*6*5*4*3*2*1) = 362880
To convert a Deterministic Finite Automaton (DFA) to a regular expression using a DFA to regular expression converter, you can follow these steps: Input the DFA into the converter. The converter will analyze the transitions and states of the DFA. It will then generate a regular expression that represents the language accepted by the DFA. The regular expression will capture the patterns and rules of the DFA in a concise form. By using a DFA to regular expression converter, you can efficiently convert a DFA into a regular expression without having to manually derive it.