-21, -20, -19, and -18
While that is correct it would be better to show how to get the answer.
the 4 consecutive integers would be represented by x, x+1, x+2, x+3
now the sum would be -78
so you have x+x+1+x+2+x+3=-78
Reduce and solve for x
4x+6=-78
4x=-84
x=-21
so, x=-21 then x+1 = -20, x+2 = -19 and x+3=-18
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The integers are 17, 19, 21 and 23.
17 , 19 , 21 and 23 are the odd integers whose sum is 80 and the least integer is 17
No. There is no set of three consecutive even integers with a sum of 40.
The integers are 20 and 22.
31 32 33