10 %
30 percent of 20 percent of 150 percent = 0.09
0.900 percent = 0.90 percent = 0.9 percent = 9/10 percent 0.900 percent = 0.009 0.900 = 90 percent
1 percent of a percent is 1/10000 or 0.0001; this is the same as saying 1 percent percent. Example: 5 percent percent is 0.0005, so 5 percent percent of 100 is 0.0005 x 100 or 0.05.
Parsing the question: What percent of 10 percent of 50 is 25 percent of 100? What percent of 10 percent of 50 is 25? What percent of 5 is 25? Answer: 500%
60 percent as a percent is 60%
.o1 uF
bulbasaur!i like charizard better!
O2- in oxides, O1- in peroxides
#include<stdio.h> #include<conio.h> #include<string.h> #include<stdlib.h> #include<process.h> void main() { clrscr(); char *s1,*s2,*o1,*o2,temp1,temp2; printf("Enter first statement:"); gets(s1); printf("Enter second statement:"); gets(s2); if(s1[0]!=s2[0]) { printf("Sorry"); getch(); exit(0); } o1[0]=s1[0]; o1[1]='-'; o1[2]='>'; for(int i=3;s1[i]==s2[i];i++) o1[i]=s1[i]; temp1=i; temp2=i; o1[i++]='Z'; o1[i++]='\0'; o2[0]='Z'; o2[1]='-'; o2[2]='>'; int p=3; for(int j=temp1;j<strlen(s1);j++) { o2[p]=s1[j]; p++; } o2[p++]='/'; for(j=temp2;j<strlen(s2);j++) { o2[p]=s2[j]; p++; } o2[p++]='\0'; puts(o1); puts(o2); getch(); }
0.1 litre = 10 centilitres
O1 visa
Usually two oxegen atoms (O2) though can be one (O1).
Usually two oxegen atoms (O2) though can be one (O1).
they catch the ball. but there is to o1 on each team catches against the separate team
700,000,000,000,000.O1
12 teenagers can eat 12 pizzas in one-and-a-half days so they can eat 48 in 6 days I always had difficulty with these problems. It is computed as follows: If P1 people can eat O1 objects in T1 days then P2 people can eat O2 objects in T2 days P1T1/O1 = P2T2/O2 In the example P1 = 1.5 T1 = 1.5 O1 = 1.5 P2 = 12 T2 = 6 solve for O2: O2 = P2 O1 T2/ P1 T1 = 48
6 inches in one half foot.