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2.25 gallons

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Q: What is the 15 percent of 15 gallons?
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What is 15 percent of ten gallons?

15% of 10 gallons = 10*15/100 = 1.5 gallons.


What is 15 percent of 2.4 gallons?

15% of 2.4 US gallons= 15% * 2.4= 0.15 * 2.4= 0.36 US gallons or 46.08 US fluid ounces


How do you dilute 500 gallons of 31 percent to 15 percent?

To dilute 500 gallons of a 31% solution to a 15% solution you would add 533.33 gallons of the dilutant. For example, if you have 500 gallons of a 31% saline solution you would add 533.33 gallons of water to create 1033.33 gallons of a 15% saline solution.


How many gallons of a 80 percent antifreeze solution must be mixed with 60 gallon of 15 percent antifreeze to get a mixture that's 70 percent antifreeze?

330 gallons of 80% antifreeze mixed with 60 gallons of 15% antifreeze will provide 390 gallons of 70% antifreeze. Let the multiplier of 60 gallons be x, then considering the percentages of antifreeze in the solutions: (15 + 80x) ÷ (1 + x) = 70 ⇒ 15 + 80x = 70 + 70x ⇒ 10x = 55 ⇒ x = 5.5 Therefore mix 60 x 5.5 = 330 gallons of 80% antifreeze.


How much pure acid should be mixed with 6 gallons of a 50 percent acid solution in order to get an 80 percent acid solution?

50% acid in a 6 gallon solution means that 3 gallons are acid. 9 gallons more acid will give you a total of 12 gallons of acid in a 15 gallon solution. 12 is 80% of 15.


What is 25 percent of 10 gallons?

25 percent of 10 gallons is 2.5 gallons.


What is 20 percent of 50 gallons?

20 percent of 50 gallons is 10 gallons. You can find this by multiplying 50 by 0.20.


What is 1.5 percent of 1 liter?

15 milliliters 0.0158503231 quarts 0.00396258079 gallons 0.507210341 fluid ounces


How many gallons of a 50 percent antifreeze solution must be mixed with 90 gallons of 25 percent antifreeze to get a mixture of 40 percent antifreeze?

135 gallons. Let the multiple of 90 gallons to add be x, then using the percentages of antifreeze in the solutions: (25 + 50x) ÷ (1 + x) = 40 ⇒ 25 + 50x = 40 + 40x ⇒ 10x = 15 ⇒ x = 1.5 Therefore add 90 x 1.5 = 135 gallons.


How many gallons of 50 percent antifreeze solution must be mixed with 70 gallons of 25 percent antifreeze to get a mixture that is 40 percent antifreeze?

105 gallons. Let the multiple of 70 gallons to add be x, then using the percentages of antifreeze in the solutions: (25 + 50x) ÷ (1 + x) = 40 ⇒ 25 + 50x = 40 + 40x ⇒ 10x = 15 ⇒ x = 1.5 Therefore add 70 x 1.5 = 105 gallons.


What is 10 percent of 10 gallons?

10 percent of 10 gallons is 1 gallon.


What is 46 percent of 340 gallons?

46% of 340 gallons= 46% * 340= 0.46 * 340= 156.4 gallons