25 percent of 10 gallons is 2.5 gallons.
10 percent of 10 gallons is 1 gallon.
70 percent out of 5 gallons = 3.5 gallons70% of 5 gallons= 70% * 5 gallons= 70%/100% * 5 gallons= 35/10 or 3.5 gallons
175 gallons.
0.3 gallons.
15% of 10 gallons = 10*15/100 = 1.5 gallons.
15% of 2.4 US gallons= 15% * 2.4= 0.15 * 2.4= 0.36 US gallons or 46.08 US fluid ounces
To dilute 500 gallons of a 31% solution to a 15% solution you would add 533.33 gallons of the dilutant. For example, if you have 500 gallons of a 31% saline solution you would add 533.33 gallons of water to create 1033.33 gallons of a 15% saline solution.
330 gallons of 80% antifreeze mixed with 60 gallons of 15% antifreeze will provide 390 gallons of 70% antifreeze. Let the multiplier of 60 gallons be x, then considering the percentages of antifreeze in the solutions: (15 + 80x) ÷ (1 + x) = 70 ⇒ 15 + 80x = 70 + 70x ⇒ 10x = 55 ⇒ x = 5.5 Therefore mix 60 x 5.5 = 330 gallons of 80% antifreeze.
50% acid in a 6 gallon solution means that 3 gallons are acid. 9 gallons more acid will give you a total of 12 gallons of acid in a 15 gallon solution. 12 is 80% of 15.
25 percent of 10 gallons is 2.5 gallons.
20 percent of 50 gallons is 10 gallons. You can find this by multiplying 50 by 0.20.
15 milliliters 0.0158503231 quarts 0.00396258079 gallons 0.507210341 fluid ounces
135 gallons. Let the multiple of 90 gallons to add be x, then using the percentages of antifreeze in the solutions: (25 + 50x) ÷ (1 + x) = 40 ⇒ 25 + 50x = 40 + 40x ⇒ 10x = 15 ⇒ x = 1.5 Therefore add 90 x 1.5 = 135 gallons.
105 gallons. Let the multiple of 70 gallons to add be x, then using the percentages of antifreeze in the solutions: (25 + 50x) ÷ (1 + x) = 40 ⇒ 25 + 50x = 40 + 40x ⇒ 10x = 15 ⇒ x = 1.5 Therefore add 70 x 1.5 = 105 gallons.
10 percent of 10 gallons is 1 gallon.
46% of 340 gallons= 46% * 340= 0.46 * 340= 156.4 gallons