162 2, 81 2, 9, 9 2, 3, 3, 3, 3
2/3= 2 ÷3= 0.66679/12= 9 ÷12= 0.75therefore, 9/12 is greater than 2/3.
-15
1 and 2/3 ft. by 2 ft. 50 cm x 60 cm
29/39 2/3:= [(3 * 9)+2]/3= [27+2]/3= 29/3 in improper fraction
3cm x 3cm = 9 cm^(2(.
It is 9/2*sqrt(3) = 7.79 cm approx.
2 * 9 cm + 2 * 4 cm = 18 cm + 8 cm = 26 cm or 9+9+4+4=26cm
Well honey, if you're looking to fill up a box that's 3 cm long, 2 cm wide, and 2 cm deep, you're gonna need a total of 12 cubic centimeters to fill that bad boy up. It's simple math, nothing fancy about it. Just remember, it's always better to have too much space than not enough, just like in life!
9*9 = 81 square cm
There are 100 cm in 1 meter. Therefore, 2 meters is equal to 200 cm. Adding 9 cm to this gives a total of 209 cm in 2 meters 9 cm.
The area of a circle is pi times radius times radius. 6 cm = 2 times 3 cm radius = 3 cm. SO, pi times 3 cm times 3 cm 9 pi pi is approximately 3.141592... 9 times 3.141592... is 28.274328...
V = Bh or V = πr^2h Since diameter is 6 cm, then radius is 3 cm. Substitute what you know into the formula and you have: 342 cm^3 = π[(3 cm)^2]h 342 cm^3 = π(9 cm^2]h divide by 9 cm^2 to both sides 38 cm = πh divide by π to both sides 38 cm/π = h or h = 38 cm/π h ≈ 12 cm
It can have any area greater than 0 cm2 and less than or equal to 81(3-√8) ≈ 13.897 cm2. Without further information that provides the length of (at least) one side it is impossible to say which of these areas the triangle has. For example: base = 9 cm, hypotenuse = 9 cm ⇒ height = 18 - 9 - 9 cm = 0 cm ⇒ area = 9x0/2 = 0 cm2 This triangle does not actually exist and represents the minimum of the area. base = 6 cm, hypotenuse = 7.5 cm ⇒ height = 18 - 6 - 7.5 cm = 4.5 cm ⇒ area = 6x4.5/2 = 12.5 cm2 Note that base2 + height2 = 36 + 20.25 = 56.25 = 7.52 = hypotenuse2 and so this is a right angle triangle. base = 9(2-√2) cm ≈ 5.272 cm, hypotenuse = 18(√2 -1) cm ≈ 7.456 cm ⇒ height = 18 - 9(2-√2) - 18(√2 -1) cm = 9(2-√2) cm ≈ 5.272 cm ⇒ area = 9(2-√2) x 9(2-√2)/2 = 81(3-√8) cm2 ≈ 13.897 cm2 This triangle is a right angle triangle (check out Pythagoras on the lengths) and is the right angle triangle of largest area with perimeter 18 cm.
Let the width be x and the length be y So: 2x+2y = 5x implying that y = 1.5x If: xy = 130 and 2/3 Then: x(1.5x) = 130 and 2/3 => 1.5x squared = 130 and 2/3 Divide both sides by 1.5 and then square root both sides: x = 9 and 1/3 cm Length: 130 and 2/3 divided by 9 and 1/3 = 14 cm Therefore: length = 14 cm and width = 9 and 1/3 cm
Which dimensions are which? For a base of 2 cm, height of 3 cm, and length of 2 cm it would be 5 cm^3. It would be the same if the base were 3 cm, but if the length were 3 cm it would instead be 6 cm^3.
1 cm = 10 mm 2 cm = 20 mm 3 cm = 30 mm . . 9 cm = 90 mm That's more than 77 mm.