The GCF is 9.
Since 27 is a factor of 54, it is automatically the GCF of this problem.27. 27*2=54.Since 27 is a factor of 54, it is automatically the GCF of this problem.
The GCF of 27 x^2 y^3 and 46 x^2 y is xy^2. 27 and 46 are coprime.
The gcf is 1. The only factors of 27 are 3,3, and 3. The only factors of 52 are 2, 2, and 13. So, 1 is the greatest factor.
The GCF is 9.
The GCF of 14 and 48 is 2. The GCF of 81 and 135 is 27. The GCF of all four is 1.
The GCF is 9.
The GCF is 27b.
Since 27 is a factor of 54, it is automatically the GCF of this problem.27. 27*2=54.Since 27 is a factor of 54, it is automatically the GCF of this problem.
The GCF is 27.
27 and 54
The GCF of 18, 4 and 27 is 1. I saw this straight away as 4 only has factors of 4, 2 and 1. 4 or 2 don't go into 27. Therefore the GCF has to be 1.
40 - 1, 2, 4, 5, 8, 10, 20, 40 27 - 1, 3, 9, 27 the GCf is just 1
The GCF is 27.
gcf(12, 48, 27) = 3. 12 = 2^2 x 3 48 = 2^4 x 3 27 = 3^3 hcf = 3
The GCF of 18, 27, and 78 is 3.18=2*3*327=3*3*378=2*3*13GCF=3
You need at least two numbers to find a GCF. If that's 2 and 79, the GCF is 1. If that's 27 and 9, the GCF is 9.